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0=5y^2-30y+5
We move all terms to the left:
0-(5y^2-30y+5)=0
We add all the numbers together, and all the variables
-(5y^2-30y+5)=0
We get rid of parentheses
-5y^2+30y-5=0
a = -5; b = 30; c = -5;
Δ = b2-4ac
Δ = 302-4·(-5)·(-5)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-20\sqrt{2}}{2*-5}=\frac{-30-20\sqrt{2}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+20\sqrt{2}}{2*-5}=\frac{-30+20\sqrt{2}}{-10} $
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